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Posts Tagged ‘eric the half a bee’

And now for something completely different…

Posted by Encota on 11 August 2017

OK.  We’ve done the sums.  The answer could be either 4 1/2 or 72.

Inspect the grid.  There are only five pairs of unambiguous letters B (hereafter known as Bs, or Bees) in the grid not separated by a Bar.  Convert these pairs of Bs from Bs to five Bees.  [And obviously 72 is way too big so can be ignored 🙂 ]

That leave minus Half A Bee to be found.  The Preamble talks about one ambiguity: clearly this is the possibility of the third letter of 25 across – is it an O or an E?

Use your favourite means for picking O(dd) or E(ven).  I keep a six foot insect-carved version of the 18th Century gambling game known as E-O in the billiard room for exactly this purpose.  The ball falls in Even, so E it is.  Row 7 now contains ERIC (the half a bee).  For those that need reminding, try

Finally subtract half a bee using the usual accounting convention of placing it in brackets. We now have five bees, less half a bee: 4 1/2 bees now found.  Simples.

2017-07-23 13.54.06

Tim / Encota

P.S. And the ‘Eric The Half A Bee’ Python song’s lyrics include, if I heard them right:

Half a bee, cruciverbally
Must either sail, or rival 3…

[Good grief!  Ed.]

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